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16x^2+9.6x+0=0
We add all the numbers together, and all the variables
16x^2+9.6x=0
a = 16; b = 9.6; c = 0;
Δ = b2-4ac
Δ = 9.62-4·16·0
Δ = 92.16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9.6)-\sqrt{92.16}}{2*16}=\frac{-9.6-\sqrt{92.16}}{32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9.6)+\sqrt{92.16}}{2*16}=\frac{-9.6+\sqrt{92.16}}{32} $
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